x^+19x+22=8x+4

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Solution for x^+19x+22=8x+4 equation: 



x^+19x+22=8x+4

We move all terms to the left:

x^+19x+22-(8x+4)=0

We add all the numbers together, and all the variables

20x-(8x+4)+22=0

We get rid of parentheses

20x-8x-4+22=0

We add all the numbers together, and all the variables

12x+18=0

We move all terms containing x to the left, all other terms to the right

12x=-18

x=-18/12

x=-1+1/2

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